(3x^2-6)-(x^2+1)=

Solution for (3x^2-6)-(x^2+1)= equation:

Simplifying
(3x2 + -6) + -1(x2 + 1) = 0

Reorder the terms:
(-6 + 3x2) + -1(x2 + 1) = 0

Remove parenthesis around (-6 + 3x2)
-6 + 3x2 + -1(x2 + 1) = 0

Reorder the terms:
-6 + 3x2 + -1(1 + x2) = 0
-6 + 3x2 + (1 * -1 + x2 * -1) = 0
-6 + 3x2 + (-1 + -1x2) = 0

Reorder the terms:
-6 + -1 + 3x2 + -1x2 = 0

Combine like terms: -6 + -1 = -7
-7 + 3x2 + -1x2 = 0

Combine like terms: 3x2 + -1x2 = 2x2
-7 + 2x2 = 0

Solving
-7 + 2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 2x2 = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 2x2 = 0 + 7
2x2 = 0 + 7

Combine like terms: 0 + 7 = 7
2x2 = 7

Divide each side by '2'.
x2 = 3.5

Simplifying
x2 = 3.5

Take the square root of each side:
x = {-1.870828693, 1.870828693}